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NEW QUESTION: 1
A. Option A
B. Option C
C. Option D
D. Option B
Answer: B,C
NEW QUESTION: 2
You are the HR manager lot a company that uses Microsoft Dynamics 365 for Talent You want to set up a leave and absence plan for a group of employees from your company so they will be able to take parental leave.
What should you do?
A. You should create a leave and absence plan, and ask the employees to select the plan when requesting time off.
B. You should create a leave and absence type and leave and absence plan, and assign the leave and absence plan to the appropriate employees.
C. You should create a leave and absence type and leave and absence plan, and assign the leave and absence type to the appropriate employees.
D. You should create a leave and absence type, and ask the employees to select the type when requesting time off.
Answer: A
NEW QUESTION: 3
SysOps管理者は次のバケットポリシーを実装して、企業IPアドレス範囲54.240.143.0/24のみがAmazon S3バケット内のオブジェクトにアクセスできるようにしました。
一部の従業員は、企業のIPアドレス範囲外のIPアドレスからS3バケットにアクセスできると報告しています。
管理者はこの問題にどのように対処できますか？
A. Condition要素をIAMポリシーからaws：SourceIpではなくaws：StringEqualsに変更します。
B. S3バケットへの不正アクセスを防ぐために、NotIpAddressとIpAddressの両方を含めるように条件演算子を変更します。
C. ポリシーの2番目のステートメントで、効果をAllowからDenyに変更して、ソースIP範囲からではない要求を拒否します。
D. バケットポリシーの代わりにIAMポリシーを変更して、ユーザーがソースIPアドレスに基づいてバケットにアクセスするのを制限します。
Answer: C
NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:
Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: A
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1