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NEW QUESTION: 1
Auto ScalingグループのEC2インスタンスで構成されるアプリケーションがあります。毎日特定の時間枠の間に、あなたのウェブサイトへのトラフィックが増加しています。
したがって、ユーザーはアプリケーションの応答時間が遅いことに不満を持っています。 CPU使用率が次の値を超えたときに1つの新しいEC2インスタンスをデプロイするようにAuto Scalingグループを設定しました
5分間の2つの連続した期間で60％。
この問題を解決するための最も費用効果の低い方法は何ですか？
A. 新しいインスタンスをデプロイするためのしきい値CPU使用率を減らします
B. 収集期間を10分に減らします
C. 収集期間の連続数を減らす
D. Auto Scalingグループのインスタンスの最小数を増やします
Answer: D
Explanation:
If you increase the minimum number of instances, then they will be running even though the load is not high on the website. Hence you are incurring cost even though there is no need. All of the remaining options are possible options which can be used to increase the number of instances on a high load.
For more information on On-demand scaling, please refer to the below link:
http://docs.aws.amazon.com/autoscaling/latest/userguide/as-scale-based-on-demand. html Note: The tricky part where the question is asking for 'least cost effective way". You got the design consideration correctly but need to be careful on how the question is phrased.
NEW QUESTION: 2
CloudFormationテンプレートのポリシーを使用して、特定のIAMユーザーのみがアクセスできるS3バケットを作成することはできますか？
A. いいえ、同じテンプレートでは、S3バケットと現実的なポリシーのみを作成できます。
B. はい、これらすべてのリソースはCloudFormationテンプレートを使用して作成できます
C. いいえ、作成できるのはS3バケットのみで、IAMユーザーはできません。
D. S3はCloudFormationでサポートされていません。
Answer: B
Explanation:
AWS Identity and Access Management（IAM）を使用すると、IAMユーザーを作成して、AWSアカウントのどのリソースに誰がアクセスできるかを制御できます。
IAMとAWS CloudFormationを使用して、スタックテンプレートの表示、スタックの作成、スタックの削除など、ユーザーが実行できるAWS CloudFormationアクションを制御できます。
AWS CloudFormationアクションに加えて、各ユーザーが利用できるAWSサービスとリソースを管理できます。
NEW QUESTION: 3
소셜 미디어 회사는 Amazon Cognito를 사용하여 다양한 모바일 장치에서 프로파일을 동기화함으로써 최종 사용자가 원활한 경험을 할 수 있도록합니다.
다음 구성 중 다른 장치에서 업데이트를 사용할 수 있을 때마다 자동으로 사용자에게 알리는 데 사용할 수있는 구성은 무엇입니까?
A. 푸시 동기화 기능을 적절한 IAM 역할과 함께 사용합니다.
B. SyncCallback 인터페이스를 사용하여 애플리케이션의 알림을 수신합니다.
C. Amazon Cognito 스트림을 사용하여 데이터를 분석하고 알림을 푸시합니다.
D. 동기화를 유지하는 모든 장치를 포함하도록 사용자 풀을 수정합니다.
Answer: C
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t1[]={3,2,4,1,5};
int t2[]={5,6,8,2,1};
vector<int> v1(10);
sort(t1, t1+5);
sort(t2, t2+5);
set_difference(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<int>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 3 4 0 0 0 0 0 0 0 0
B. 1 2 5 0 0 0 0 0 0 0
C. compilation error
D. 6 8 0 0 0 0 0 0 0 0
E. 1 2 3 4 5 6 8 0 0 0
Answer: A