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NEW QUESTION: 1
Your network consists of a single Active Directory domain named contoso.com. All servers run Windows Server 2003 Service Pack 2 (SP2).
The domain contains a domain Distributed File System (DFS) root named DFSroot. The network contains the offices shown in the following table.
Server1 and Server2 currently each host a share named Applications.
You need to implement a solution to meet the following requirements: Automatically redirect users to the
Applications folder in their local site.
Ensure that the contents of the Applications shares on Server1 and Server2 are automatically synchronized.
What should you do?
A. In the DFS root, create a root target that points to \\server1\applications. Create a second root target that points to \\server2\applications.
B. In the DFS root, create one link named Applications that has \\server1\applications and \\server2 \applications as targets.
C. In the DFS root, create one link named Applications1 that has \\server1\applications as its target. Create a second link named Applications2 that has \\server2\applications as its target.
D. In the Main office computers OU, publish the \\server1\applications share. In the Branch office computers OU, publish the \\server2\applications share.
Answer: B
NEW QUESTION: 2
A user is creating a report with a 1-inch margin all around for the entire report. Which document type should be selected?
A. Normal
B. Page Setup
C. Header
D. Footer
Answer: B
NEW QUESTION: 3
データベースDB1があります。
3つの異なるテーブルに行を挿入するストアドプロシージャを作成する予定です。各挿入は各テーブルに同じ識別値を使用する必要がありますが、値はストアード・プロシージャーの呼び出しごとに増えていく必要があります。
場合によっては、識別値を初期値にリセットする必要があります。使用するストアドプロシージャの識別値を保持するためのメカニズムを設計する必要があります。
あなたは何をするべきか？複数の回答を選択することで目的を達成することができます。最良の答えを選択してください。
A. 3つの各テーブルにID列を作成します。各テーブルに同じシードと同じ増分を使用します。ストアドプロシージャを使用して新しい行をテーブルに挿入します。必要に応じてDBCC CHECKIDENTコマンドを使用します。
B. シーケンス内の次の値を保持するシーケンスオブジェクトを作成します。ストアドプロシージャを使用して次の値を取得します。必要に応じてALTER SEQUENCE文を使用して値をリセットします。
C. シーケンス内の次の値を保持するシーケンスオブジェクトを作成します。ストアドプロシージャを使用して次の値を取得します。ALTER SEQUENCE文を使用してシーケンスオブジェクトを次の値に増分します。異なるALTER SEQUENCE文。
D. シーケンス内の次の値を保持する4番目のテーブルを作成します。各トランザクションが終了したら、ストアドプロシージャを使用して値を更新します。必要に応じてUPDATEステートメントを使用して値をリセットします。
Answer: B
Explanation:
Explanation
- an application can obtain the next sequence number without inserting the row by calling the NEXT VALUE FOR function.
- ALTER SEQUENCE Includes argument:
RESTART [ WITH <constant> ]
The next value that will be returned by the sequence object. If provided, the RESTART WITH value must be an integer that is less than or equal to the maximum and greater than or equal to the minimum value of the sequence object. If the WITH value is omitted, the sequence numbering restarts based on the original CREATE SEQUENCE options.
- CREATE SEQUENCE
Creates a sequence object and specifies its properties. A sequence is a user-defined schema bound object that generates a sequence of numeric values according to the specification with which the sequence was created.
The sequence of numeric values is generated in an ascending or descending order at a defined interval and can be configured to restart (cycle) when exhausted.