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NEW QUESTION: 1
Which three statements about DTP are true? (Choose three.)
A. It is a Layer 3-based protocol.
B. It is disabled by default.
C. It is a universal protocol.
D. It is a Layer 2-based protocol.
E. It is a proprietary protocol.
F. It is enabled by default.
Answer: D,E,F
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 2
A. Option C
B. Option B
C. Option E
D. Option D
E. Option A
Answer: E
Explanation:
On R4, in the redistribution of EIGRP routing protocol, we need to change name of route-map to resolve the issue. It references route-map OSPF_to_EIGRP but the actual route map is called OSPF->EIGRP.
========================================================================== =====
Topic 14, Ticket 9 : EIGRP AS number
Topology Overview (Actual Troubleshooting lab design is for below network design)
-Client Should have IP 10.2.1.3 -EIGRP 100 is running between switch DSW1 & DSW2 -OSPF (Process ID 1) is running between R1, R2, R3, R4 -Network of OSPF is redistributed in EIGRP -BGP 65001 is configured on R1 with Webserver cloud AS 65002 -HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process
number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where
necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002
in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and
outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running
on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number
6.DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the
underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same. Question-1 Fault is found on which device, Question-2 Fault condition is related to, Question-3 What exact problem is seen & what needs to be done for solution ==========================================================================
=====
Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4 ipconfig ----- Client will be receiving IP address 10.2.1.3
-From Client PC we can ping 10.2.1.254 -But IP 10.2.1.3 is not able to ping from R4, R3, R2, R1 -This clearly shows problem at R4 Kindly check routes in EIGRP there are no routes of eigrp. -Check the neighborship of EIGRP on R4; there are no neighbor seen from DSW1 & DSW2
check the running config of EIGRP protocol it shows EIGRP AS 1 process.... Now check on DSW1 & DSW2 On DSW1 only one Eigrp neighbour is there with DSW2 but its not with R4...
-From above snapshot & since R4 has EIGRP AS number 1 due to which neighbour is not happening.
-Change required: On R4, IPV4 EIGRP Routing, need to change the EIGRP AS number from 1 to 10 since DSW1 & DSW2 is configured to be in EIGRP AS number 10.
NEW QUESTION: 3
Where parties do not have a shared secret and large quantities of sensitive information must be passed, the most efficient means of transferring information is to use Hybrid Encryption Methods. What does this mean?
A. Use of software encryption assisted by a hardware encryption accelerator.
B. Use of public key encryption to secure a secret key, and message encryption using the secret key.
C. Use of the recipient's public key for encryption and decryption based on the recipient's private key.
D. Use of elliptic curve encryption.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
For large quantities of sensitive information, symmetric key encryption (using a secret key) is more efficient.
Public key cryptography uses two keys (public and private) generated by an asymmetric algorithm for protecting encryption keys and key distribution, and a secret key is generated by a symmetric algorithm and used for bulk encryption. Then there is a hybrid use of the two different algorithms: asymmetric and symmetric. Each algorithm has its pros and cons, so using them together can be the best of both worlds.
In the hybrid approach, the two technologies are used in a complementary manner, with each performing a different function. A symmetric algorithm creates keys used for encrypting bulk data, and an asymmetric algorithm creates keys used for automated key distribution.
When a symmetric key is used for bulk data encryption, this key is used to encrypt the message you want to send. When your friend gets the message you encrypted, you want him to be able to decrypt it, so you need to send him the necessary symmetric key to use to decrypt the message. You do not want this key to travel unprotected, because if the message were intercepted and the key were not protected, an evildoer could intercept the message that contains the necessary key to decrypt your message and read your information. If the symmetric key needed to decrypt your message is not protected, there is no use in encrypting the message in the first place. So we use an asymmetric algorithm to encrypt the symmetric key. Why do we use the symmetric key on the message and the asymmetric key on the symmetric key?
The reason is that the asymmetric algorithm takes longer because the math is more complex. Because your message is most likely going to be longer than the length of the key, we use the faster algorithm (symmetric) on the message and the slower algorithm (asymmetric) on the key.
Incorrect Answers:
B: For large quantities of sensitive information, symmetric key encryption (using a secret key) is more efficient. Using public and private keys for encryption and decryption is asymmetric key encryption.
C: Software encryption is not an answer on its own. We need to determine what type of software encryption to use.
D: Elliptical curve cryptography (ECC) is a public key encryption technique. Symmetric key encryption is more efficient for large amounts of data.
References:
Harris, Shon, All In One CISSP Exam Guide, 6th Edition, McGraw-Hill, 2013, p. 793
NEW QUESTION: 4
Which statement about what happens to a Cisco IOS SIP VoIP dial-peer that never received any responses to its out-of-dialog OPTIONS ping is true?
A. Its admin and operational state will be down.
B. Its admin state will be up but operational state will be "busy-out".
C. Its admin and operational state will be "busy-out".
D. Its admin and operational state will remain up.
E. Its admin state will be up but operational state will be down.
Answer: E
Explanation:
You can check the validity of your dial peer configuration by performing the following tasks:
If you have relatively few dial peers configured, you can use the show dial-peer voice command
to verify that the configuration is correct. To display a specific dial peer or to display all configured
dial peers, use this command. The following is sample output from the show dial-peer voice
command for a specific VoIP dial peer:
router# show dial-peer voice 10
VoiceOverIpPeer10
tag = 10, dest-pat = \Q',
incall-number = \Q+14087',
group = 0, Admin state is up, Operation state is down
Permission is Answer,
type = voip, session-target = \Q',
sess-proto = cisco, req-qos = bestEffort,
acc-qos = bestEffort,
fax-rate = voice, codec = g729r8,
Expect factor = 10,Icpif = 30, VAD = disabled, Poor QOV Trap = disabled,
Connect Time = 0, Charged Units = 0
Successful Calls = 0, Failed Calls = 0
Accepted Calls = 0, Refused Calls = 0
Last Disconnect Cause is ""
Last Disconnect Text is ""
Last Setup Time = 0
To show the dial peer that matches a particular number (destination pattern), use the show dialplan number command. The following example displays the VoIP dial peer associated with the destination pattern 51234: router# show dialplan number 51234 Macro Exp.: 14085551234 VoiceOverIpPeer1004 tag = 1004, destination-pattern = \Q+1408555....', answer-address = \Q', group = 1004, Admin state is up, Operation state is up type = voip, session-target = \Qipv4:1.13.24.0', ip precedence: 0 UDP checksum = disabled session-protocol = cisco, req-qos = best-effort, acc-qos = best-effort, fax-rate = voice, codec = g729r8, Expect factor = 10, Icpif = 30, VAD = enabled, Poor QOV Trap = disabled Connect Time = 0, Charged Units = 0 Successful Calls = 0, Failed Calls = 0 Accepted Calls = 0, Refused Calls = 0 Last Disconnect Cause is "" Last Disconnect Text is "" Last Setup Time = 0 Matched: +14085551234 Digits: 7 Target: ipv4:172.13.24.0