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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains two servers named Server1 and Server2 that run Windows Server 2016.
Server1 has Microsoft System Center 2016 Virtual Machine Manager (VMM) installed. Server2 has IP Address Management (IPAM) installed.
You create a domain user named User1.
You need to integrate IPAM and VMM. VMM must use the account of User1 to manage IPAM. The solution must use the principle of least privilege.
What should you do on each server? To answer, select the appropriate options in the answer area.
Answer:
Explanation:
Explanation
References:
https://technet.microsoft.com/en-us/library/dn783349(v=ws.11).aspx
NEW QUESTION: 2
Welche der folgenden Aussagen zu Softwareentwicklungsmodellen ist am genauesten? [K1]
A. Das 4-Stufen-V-Modell ist immer die beste Wahl für ein Softwareentwicklungsmodell für jedes Projekt
B. Das agile Entwicklungsmodell eignet sich normalerweise am besten für kurze Projekte
C. Die Wahl des Softwareentwicklungsmodells hängt von den Produkt- und Projekteigenschaften ab
D. Das 2-Stufen-V-Modell ist das am besten geeignete Entwicklungsmodell für einfache Produkte
Answer: C
NEW QUESTION: 3
Examine the commands used to create DEPARTMENT_DETAILS and
COURSE_DETAILS:
SQL>CREATE TABLE DEPARTMENT_DETAILS
(DEPARTMENT_ID NUMBER PRIMARY KEY,
DEPARTMENT_NAMEVARCHAR2(50),
HODVARCHAR2(50));
SQL>CREATE TABLE COURSE_DETAILS
(COURSE_IDNUMBER PRIMARY KEY,
COURSE_NAMEVARCHAR2(50),
DEPARTMENT_IDVARCHAR2(50));
You want to generate a list of all department IDs along with any course IDs that may have been assigned to them.
Which SQL statement must you use?
A. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (d.department_id=c. department_id);
B. SELECT d.department_id, c.course_id FROM course_details c LEFT OUTER JOIN department_details d ON (c.department_id=d. department_id);
C. SELECT d.department_id, c.course_id FROM department_details d RIGHT OUTER JOIN course_details c ON (c.department_id=d. department_id);
D. SELECT d.department_id, c.course_id FROM department_details d LEFT OUTER JOIN course_details c ON (d.department_id=c. department_id);
Answer: D