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NEW QUESTION: 1
Which three of the following folders should NOT be publicly accessible? (Choose THREE.)
A. /app/design/frontend/package/theme/template
B. /skin/frontend/package/theme/js
C. /skin/frontend/package/theme/css
D. /app/design/frontend/package/theme/locale
E. /app/design/frontend/package/theme/layout
F. /skin/frontend/package/theme/img
Answer: A,D,E
NEW QUESTION: 2
あなたの組織は、非常に高い離職率を持つ高度に規制された業界の一部です。新入社員のライセンスをリサイクルし、データ保持規制に準拠するために、特定のGSuiteデータを別のバックアップ環境に保存する必要があると判断されました。
この状況のデータをどのように保存する必要がありますか？
A. ルーティングルールを使用して、オンプレミスのSMTPサーバーとGSuiteにメールを二重配信します。
B. スクリプトを作成し、G SuiteAPIを使用してユーザーデータにアクセスしてダウンロードします。
C. Googleデータエクスポートを使用し、アーカイブをローカルに保存するようにユーザーをトレーニングします。
D. サードパーティのツールを使用して、GSuiteデータの安全なバックアップを設定します。
Answer: D
NEW QUESTION: 3
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die folgenden Anforderungen erfüllt sind:
* Die Einstufung der Schüler muss anhand ihrer Durchschnittsnote erfolgen.
* Wenn ein oder mehrere Schüler den gleichen Durchschnitt haben, müssen diese Schüler den gleichen Rang erhalten.
* Aufeinanderfolgende Ränge müssen übersprungen werden, wenn derselbe Rang zugewiesen wird.
Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1
B. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
C. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
D. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
F. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
H. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
Answer: F
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx