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NEW QUESTION: 1
You are creating an application that manages information about your company's products. The application includes a class named Product and a method named Save.
The Save() method must be strongly typed. It must allow only types inherited from the Product class that use a constructor that accepts no parameters.
You need to implement the Save() method. Which code segment should you use?
A. Option C
B. Option B
C. Option D
D. Option A
Answer: C
Explanation:
Explanation
The condition new() ensures the empty/default constructor and must be the last condition.
When you define a generic class, you can apply restrictions to the kinds of types that client code can use for type arguments when it instantiates your class. If client code tries to instantiate your class by using a type that is not allowed by a constraint, the result is a compile-time error. These restrictions are called constraints.
Constraints are specified by using the where contextual keyword.
http://msdn.microsoft.com/en-us/library/d5x73970.aspx
NEW QUESTION: 2
The Ajax Corporation is designing an IP telephony network using Cisco MCS 7845 Series servers, each one capable of supporting 7500 devices. The design must meet these requirements:
-be cost-effective -support up to 7500 phones -provide a minimal level of redundancy
Which configuration will meet Ajax Corporation's needs?
A. three Cisco Unified Communications Manager servers: 1 publisher and TFTP server combined 1 primary subscriber 1 backup subscriber
B. five Cisco Unified Communications Manager servers: 1 publisher 1 TFTP server 1 primary subscriber 2 backup subscribers
C. four Cisco Unified Communications Manager servers: 1 publisher 1 TFTP server 1 primary subscriber 1 backup subscriber
D. two Cisco Unified Communications Manager servers: 1 publisher and TFTP server combined 1 primary subscriber
Answer: D
NEW QUESTION: 3
展示を参照してください。 Lakeside Companyの展示にはインターネットワークがあります。管理者は、セントラルルーターのルーティングテーブルのサイズを縮小したいと考えています。セントラルルーターのどの部分的なルーティングテーブルエントリが、フェニックスのLANを表すが追加のサブネットを持たないルートサマリを表しますか？
A. 10.0.0.0/28 is subnetted, 1 subnets
D 10.2.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
B. 10.0.0.0/22 is subnetted, 1 subnets
D 10.0.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
C. 10.0.0.0/30 is subnetted, 1 subnets
D 10.2.2.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
D. 10.0.0.0/22 is subnetted, 1 subnets
D 10.4.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
E. 10.0.0.0/30 is subnetted, 1 subnets
D 10.4.4.4 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
F. 10.0.0.0/28 is subnetted, 1 subnets
D 10.4.4.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1
Answer: D
Explanation:
10.4.0.0/22ルートには、10.4.0.0 / 24、10.4.1.0 / 24、10.4.2.0 / 24、および10.4.3.0/24のみが含まれます。