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NEW QUESTION: 1
View the Exhibit.
The shell script is executed using the default shell interpreter with the input as w. What will be the output of the script based on this input?

A. It will print the currently logged in users, current date, and time.
B. It will list all the currently logged in users.
C. It will print the current date and time.
D. It will not show any result because the case block is terminated with an esac.
E. It will show that the input is not a valid option.
Answer: E

NEW QUESTION: 2
What are valid data types for the Accounts dimension? Select all that apply.
A. Smart List
B. Percentage
C. Date
D. Text
E. Saved Assumption
F. Currency
G. Non-currency
Answer: A,B,C,D,F,G
Explanation:
Explanation/Reference:
Explanation:
Data types:
How values are stored and displayed:
*Currency (A)
*Non-Currency (B)
*Percentage (C)
*Smart List (F)
*Date (G)
*Text (E)
*Unspecified
F
or accounts, if Data Type is set to any value except Currency, you must set Exchange Rate Type to None.
Note:
The accounts dimension is a dimension type that makes accounting intelligence available. Only one dimension can be defined as Accounts.All members in the accounts dimension inherit the accounts property. You can create an outline that does not have an accounts dimension.

NEW QUESTION: 3
Kyle is performing the final testing of an application he developed for the accounting department.
His last round of testing is to ensure that the program is as secure as possible. Kyle runs the following command. What is he testing at this point?
#include <stdio.h> #include <string.h>
int main(int argc, char *argv[])
{
char buffer[10];
if (argc < 2)
{
fprintf(stderr, "USAGE: %s string\n", argv[0]);
return 1;
}
strcpy(buffer, argv[1]);
return 0;
}
A. SQL injection
B. Kernal injection
C. Buffer overflow
D. Format string bug
Answer: C
Explanation:
Answer A is the correct answer. The internal buffer is defined as a character string of 10 characters. A character string is passed as an argument. If the character string passed to the subroutine is longer than 10 characters, the buffer will overflow and parts of the stack will be overwritten.