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NEW QUESTION: 1
説明を左側から右側の暗号化アルゴリズムにドラッグアンドドロップします。
Answer:
Explanation:
Explanation
NEW QUESTION: 2
A. Option D
B. Option B
C. Option C
D. Option A
Answer: B
NEW QUESTION: 3
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
A. D:\sys\mfg\production.log 8
B. D: \sys\mfg\production.log 4
C. D:\\sys\\asm\\.\\data\\. . \\mfg\\production.log 6
D. D: \\sys\\asm\\.\\data\\. . \\mfg\\production.log 8
E. D: \\ sys\\asm\\data\\mfg\\production.log 6
Answer: A
Explanation:
The normalize method removes any redundant elements, which includes any "." or "directory/.." occurrences. The getNameCount method returns the number of elements in the path. Here there are 8 elements (in the redundant path).
Reference: The Java Tutorials,Path Operations