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NEW QUESTION: 1
Which statement about Cisco Prime is true?
A. It provides simple and efficient management of security services.
B. It is an expert-level monitoring and troubleshooting tool based on Cisco SIO.
C. It provides management services for all TrustSec products.
D. It provides simple and efficient management across architectures, networks, and services.
Answer: D
Explanation:
Topic 4, Analyze different scenarios to position Cisco core product portfolio with the customer
NEW QUESTION: 2
Cisco StackWise Virtualは、どの2つの条件で仮想リンクを介してデータを送信しますか？ （2つ選択してください。）
A. パケットはアクティブスイッチの出力インターフェイスで処理されます。
B. パケットはアクティブスイッチの入力インターフェイスで処理されます。
C. VLANはレイヤー2でフラッディングされます。
D. パケットはスタンバイスイッチの入力インターフェイスで処理されます。
E. パケットは、スタンバイスイッチの出力インターフェイスで処理されます。
Answer: B,C
NEW QUESTION: 3
Bill wants to set up a portal farm with four server instances. Which of the following statements regarding portal farms is true?
A. Session persistence is enabled by default on all four server instances..
B. All the server instances need to be configured such that they have an identical security configuration and user repository, such as LDAP.
C. Using a shared installation, all four server instances that become a part of the portal farm can be installed on different operating systems.
D. Portal and content caches across all four server instances are replicated seamlessly.
Answer: B
NEW QUESTION: 4
Given the network diagram.
Which address would successfully summarize only the networks seen?
A. 192.168.12.0/20
B. These networks cannot be summarized.
C. 192.168.16.0/21
D. 192.168.8.0/20
E. 192.168.0.0/24
F. 192.168.8.0/21
Answer: F
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you
3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
10 0000 1010
11 0000 1011
12 0000 1100
13 0000 1101
14 0000 1110
15 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0