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NEW QUESTION: 1
In the exhibit, which best describes the relationship between the two use cases:
Use Case A and Use Case B?
A. Use Case A generalizes Use CaseB.
B. Use Case B generalizes Use CaseA.
C. Use Case B includes Use CaseA.
D. Use Case A includes Use Case
E. Use Case A extends Use CaseB.
F. Use Case B extends Use CaseA.
Answer: A
NEW QUESTION: 2
What validation step is required for implementing dispute processing?
A. The Recognize Revenue Program is scheduled.
B. All transactions are of the invoice type.
C. BPM Work List for approval configuration is validated.
D. Periods for which the transaction can be disputed are Open.
Answer: C
Explanation:
Explanation/Reference:
Reference: https://docs.oracle.com/cloud/latest/financialscs_gs/FAOFC/FAOFC1478662.htm
NEW QUESTION: 3
組織では、使用するすべてのプラットフォームとテクノロジーに安全な構成基準が必要です。いずれかのシステムが安全なベースラインに準拠できない場合、組織は、システムが運用環境に配置される前に、リスクの受け入れを処理し、承認を受ける必要があります。下位の環境（開発およびステージング）に、リスクを受け入れずに非準拠のシステムが存在する場合がありますが、システムを運用環境に配置する前にリスクの承認を受ける必要があります。週次スキャンレポートは、安全なベースラインに準拠していないシステムを識別します。
アプリケーションチームは、次の結果のレポートを受け取ります。
現在、ベースライン偏差のリスク許容はありません。これはミッションクリティカルなアプリケーションであり、アプリケーションが実行されていない場合、組織は操作できません。アプリケーションは、開発およびステージング環境で完全に機能します。アプリケーションチームは次のどのアクションを実行する必要がありますか？
A. 2633のリスク受け入れを処理し、3124を修復します。
B. NYAccountingProdをシャットダウンし、異なるスキャン結果の理由を調査します。
C. 2633と3124をすぐに修正します。
D. 2633および3124のリスク許容を処理します。
Answer: A
NEW QUESTION: 4
Given the code fragment:
String h1 = "Bob";
String h2 = new String ("Bob");
What is the best way to test that the values of h1 and h2 are the same?
A. if (h1 = = h2)
B. if (h1 = = h2)
C. if (h1.same(h2))
D. if (h1.equals(h2))
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The equals method compares values for equality.
Incorrect answers:
The strings are not the same objects so the == comparison fails. See note #1 below.
As the value of the strings are the same equals is true. The equals compares values for equality.
There is no generic comparison method named same.
= = (with a space) is not a valid method.
Note: #1
Compares references, not values. The use of == with object references is generally limited to the following:
Comparing to see if a reference is null.
Comparing two enum values. This works because there is only one object for each enum constant.
You want to know if two references are to the same object.